100x^2-25x-125=0

Solution for 100x^2-25x-125=0 equation:

100x^2-25x-125=0

a = 100; b = -25; c = -125;
Δ = b2-4ac
Δ = -252-4·100·(-125)
Δ = 50625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{50625}=225$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-225}{2*100}=\frac{-200}{200}
=-1
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+225}{2*100}=\frac{250}{200}
=1+1/4
$